I put the batteries in the back of my ES and chose the lighter MT prop on the front because I was told the ES tends to be nose heavy.
Lou,Lou Rubin asked:
"Dan
Did you lose and performance with the MT? I would love to save 20 lbs off the nose. I have a foward CG?"
I never had a Hartzell on, so I don't know.
I put two Odyssey batteries in the back and an MT prop on the front hoping to take nose heaviness out, and at first I thought I over-did the adjustment, as I can't get anwhere near the front part of CG envelope. But honestly, I think I've got it about right. I have a very small amount of nose down elevator when trimmed in cruise with full fuel and only me--not sure how that compares to others--and I don't run out of nose up elevator trim when landing.
Someone knowledgeable told me some years ago that the ES is slightly faster in cruise with the Hartzell than with the MT (the person was talking like a knot or two or three), but that MT did a little better in climb. I don't know whether these points are true, but I think it is pretty hair splitting for modern constant speed propellers of the same number of blades and size. Why do I say this?
Years ago I got Hartzell to give me some performance data for the propeller used on the ES. When I plugged in book cruise numbers for the IO550 ES (the claimed book # I knew at the time was 191 KTAS at 75% power at 10,000 feet), I found that that would mean a Hartzell propeller efficiency of 0.887, which is quite good. (Design textbooks say constant speed props have efficiency in the 0.8 to 0.9 range; Gudmundsson's "General Aviation Aircraft Design" book suggests using 0.85 for the Cirrus--he was part of the design team and now teaches that stuff at Embry Riddell). This means that the % power with the Hartzell after accounting for losses due to the propeller is 0.665 [=(0.887)(0.75)]. Suppose the MT propeller for the ES has an efficiency in cruise of 0.85, which is what Gumundsson suggests using in the design process, which is 3.7 percentage points less than the Hartzell number I calculated. Percent power would fall to 0.638 [=(.85)(.75)]. It seems unlikely that MT would be any lower than that in cruise if Hartzell really is at 0.887 and Gudmundsson says use 0.85.
So what does this mean? I have a little spreadsheet I use to predict performance at different % power settings. (Basically, one inputs an observed TAS and altitude at a given % power setting, the program calculates a drag polar, and then you can change power settings and altitudes to generate KTAS predictions at different settings/altitudes using standard performance equations.) The analysis is approximate for a variety of reasons, but for small changes like this, it's going to be very accurate. That analysis predicts that if your airplane goes 191 KTAS at 75% power at 10000 feet with a propeller that has an efficiency of 0.887, then lowering the prop efficiency to 0.85 will lower your speed to ~188 KTAS.
So even if the difference between the Hartzell and MT were pretty large -- almost 4 percentage points -- we're talking about small potatoes here, basically 12 nm in a four hour flight, which is about 4 more enjoyable minutes in the air (but maybe lower bragging rights).
And my bet is that the MT actually is not 3 kts slower than the Hartzell in cruise, but I really don't know. It would be interesting to have MT's performance data for comparison, but I doubt they'd share it. When I asked the Hartzell folks at the landing about it, they didn't want to share (though they did so some years back!)
Happy and safe flying,
Dan